Python Socket Error 22 Invalid Argument


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Apr 27, 2009. File "/home/username/python/django/django/core/servers/", line 180, in runfastcgi WSGIServer(WSGIHandler(), **wsgi_opts).run() File "/home/username/ flup/server/", line 113, in run. File "/home/username/flup/server/", line 84, in run socket.error: (22, 'Invalid argument') -=–

2015年6月21日. IDE就行了)现在有了权限,开始报别的错了,提示socket.error: [Errno 22]Invalid argument。 这是创建原始套接字的代码,第一行第三个值255是IPPROTO_RAW的 值,如果要构造IP头,就要加上第二行代码设置IP_HDRINCL,第一个值0是 IPPROTO_IP的值. s=socket.socket(socket.AF_INET,socket.SOCK_RAW,255)

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File "", line 4, in <module> shutil.copy(file, dfile) File "C:Python34lib", line 228, in copy copyfile(src, dst, follow_symlinks=follow_symlinks) File "", line 107, in copyfile with open(src, 'rb') as fsrc: OSError: [Errno 22] Invalid argument: 'C:\Users\lance\Documents\*.txt'

Home > Invalid Argument > Socket.error Errno 22 Invalid Argument. Python Socket Bind Invalid Argument. but in fact do return Socket() Error Invalid Argument.

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I want to ceate Ipv6 socket at python, socket.error: (22, 'Invalid argument') ? Can anyone help me? thanks! I redo it like this, but still cannot work

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Why got the socket.error: (22, 'Invalid argument')? 0. python socket bind invalid argument was supplied. 0. throws socket.error invalid argument supplied. 1.

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Home > invalid argument > socket error 22 invalid argument. Errno 22 Invalid Argument Python. a community of 6.3 million programmers, just like you,

_IPREMOVE): try: addr = socket.gethostbyname(addr) except socket.error: raise ValueError("Invalid Hostname as argument.") naddr = 0 for naddrpos, part in enumerate(addr.split(".")): if naddrpos >= 4: raise ValueError("Address contains more than four parts.") try: if not part: part = 0 else: part = int(part) if not 0 <= part < 256:.

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. 22-einval-invalid-argument. Python Socket Error 22. the socket. Python Socket Error 22. an error is thrown? Python Socket Errno 22 Check.

I/O error. errno. ENXIO¶ No such. errno.EINVAL¶ Invalid argument. errno.ENFILE. errno.ENOTSOCK¶ Socket operation on non-socket. errno.EDESTADDRREQ.

As I wrote in post[email protected]/msg01701.html I'm still observing this socket error 22 problem but was not able to dig.

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